100x + 10y + z modulo 3
Removing 9y and 99x gives equivalence: x + y + z modulo 3
Now what’s left is induction with proper base (1-digit).
100x + 10y + z modulo 3
Removing 9y and 99x gives equivalence: x + y + z modulo 3
Now what’s left is induction with proper base (1-digit).