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you have an interesting point of view, and some of the things you have said are correct, but if you try to use gradient descent on a function from, say, ℤ → ℝ, you are going to be a very sad xanda. i would indeed describe such a function as being discontinuous not just at π but everywhere, at least with the usual definition of continuity (though there is a sense in which such a function could be, for example, scott-continuous)

even in the case of a single discontinuity in the derivative, like in relu', you lose the intermediate value theorem and everything that follows from it; it's not an inconsequential or marginally relevant fact



Note that any function ℤ → ℝ is continuous on its domain but nowhere differentiable.

A Scott-continuous function ℤ → ℝ must be monontonous. So not every such function is Scott-continuous.


aha, thanks!




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